CUET Mathematics 2022 10 Aug Shift 1 PYQs

The value of the integral $I = \int_0^1 \frac{1}{\sqrt{x^2 + 2x + 3}} dx$ is:

$\int_{\frac{\pi}{6}}^{\frac{\pi}{3}} \frac{dx}{1 + \sqrt{\tan x}}$ is equal to :

$\int_{1}^{5} |x - 2| \, dx =$