x^2 + 1/x^4 + 1 dx = Option 1: (x^4 + 1) + C Option 2: (x^2 - 1/x^2 + 1) + C Option 3: 1sqrt(2) ^-1(x^2 - 1sqrt(2) x) + C Option 4: 1sqrt(2) ^-1(x^2 + 1sqrt(2) x) + C

The answer is '1sqrt(2) ^-1(x^2 - 1sqrt(2) x) + C'. View full solution:

1sqrt(2) ^-1(x^2 - 1sqrt(2) x) + C

1sqrt(2) ^-1(x^2 + 1sqrt(2) x) + C

CUET Mathematics - x^2 + 1/x^4 + 1 dx = | PYQs + Solutions

CUET Mathematics 2022 10 Aug Shift 1

Calculus

Hard

$\log(x^4 + 1) + C$

$\log\left(\frac{x^2 - 1}{x^2 + 1}\right) + C$

$\frac{1}{\sqrt{2}} \tan^{-1}\left(\frac{x^2 - 1}{\sqrt{2} \, x}\right) + C$

$\frac{1}{\sqrt{2}} \tan^{-1}\left(\frac{x^2 + 1}{\sqrt{2} \, x}\right) + C$

✅ Correct Option: 3