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The values of y for which the distance between the points P(10, y) and Q(2, 2) is 10 unit.

Solution

✅ Correct Option: 1

By the distance formula, (10−2)2+(y−2)2=102(10-2)^2 + (y-2)^2 = 10^2.

So 64+(y−2)2=10064 + (y-2)^2 = 100, giving (y−2)2=36(y-2)^2 = 36 and y−2=±6y - 2 = \pm 6.

Hence y=8y = 8 or y=−4y = -4.

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