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The relation between A and B such that the point (A, B) is equidistant from the points (1, 3) and (2, 5) is:

Solution

✅ Correct Option: 1

Equidistant means equal squared distances:

(A−1)2+(B−3)2=(A−2)2+(B−5)2(A-1)^2+(B-3)^2=(A-2)^2+(B-5)^2

Expanding: −2A+1−6B+9=−4A+4−10B+25-2A+1-6B+9=-4A+4-10B+25

−2A−6B+10=−4A−10B+29-2A-6B+10=-4A-10B+29

2A+4B=192A+4B=19

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