If point B(0, 1) is equidistant from points A(5, -3) and C(x, 6), then find the values of x. Option 1: ± 2 Option 2: ± 8 Option 3: ± 4 Option 4: ± 5

Answer: ± 4. Solution: BA^2=BC^2. (5-0)^2+(-3-1)^2=(x-0)^2+(6-1)^2. So 25+16=x^2+25, giving x^2=16, hence x=± 4.

Geometry

Miscellaneous

Easy

If point B(0, 1) is equidistant from points A(5, -3) and C(x, 6), then find the values of x.

$\pm 2$

$\pm 8$

$\pm 4$

$\pm 5$

✅ Correct Option: 3

$BA^2=BC^2$ . $(5-0)^2+(-3-1)^2=(x-0)^2+(6-1)^2$ . So $25+16=x^2+25$ , giving $x^2=16$ , hence $x=\pm 4$ .

2022: 17 Aug Shift 1

The perimeter of the figure is.

2026: 21 May Shift 1

If A is area of regular hexagon of side 4 cm, then value of 4A (in cm $^2$ ) is:

2026: 29 May Shift 2

If Q(0, 1) is equidistant from P(5, -3) and R(x, 6), find the values of x.

2026: 12 May Shift 2

The relation between A and B such that the point (A, B) is equidistant from the points (1, 3) and (2, 5) is:

2025: 19 May Shift 1

The reflection of the point (6, - 3) on the line y = 2 is:

2023: 1 June Shift 1

An angle is $\frac{3}{7}$ times its supplementary angles. Find the angle.