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In a row of students, there are 27 students in first row, 24 in the second, 21 in the third, and so on. There are 6 students in last row. How many students are there in all row?

Solution

✅ Correct Option: 3

The numbers form an AP with first term a=27a = 27 and common difference d=−3d = -3.

Using an=a+(n−1)da_n = a + (n-1)d: 6=27−3(n−1)6 = 27 - 3(n-1), so n−1=7n - 1 = 7 and n=8n = 8 rows.

Sum =n2(a+l)=82(27+6)=4×33=132= \frac{n}{2}(a + l) = \frac{8}{2}(27 + 6) = 4 \times 33 = 132.

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