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A and B are participating in the same contest, the probability of their winning are 58\frac{5}{8} and 14\frac{1}{4} respectively. What is the probability that neither of them will win the contest?

Solution

✅ Correct Option: 4

The probability of A winning is 58\frac{5}{8} and the probability of B winning is 14\frac{1}{4}.

The probability that A does not win:

P(A doesn’t win)=1−58P(\text{A doesn't win}) = 1 - \frac{5}{8}

=38= \frac{3}{8}


The probability that B does not win:

P(B doesn’t win)=1−14P(\text{B doesn't win}) = 1 - \frac{1}{4}

=34= \frac{3}{4}


For neither A nor B to win, both events must occur together. The probabilities are multiplied:

P(Neither wins)=P(A doesn’t win)×P(B doesn’t win)P(\text{Neither wins}) = P(\text{A doesn't win}) \times P(\text{B doesn't win})

=38×34= \frac{3}{8} \times \frac{3}{4}

=932= \frac{9}{32}


The calculated answer is 932\frac{9}{32}, which equals approximately 0.2810.281 or 28.1%28.1\%.

None of the given options exactly match this answer. The mathematically correct answer is 932\frac{9}{32}, but based on the answer key provided, Option 4 (13\frac{1}{3}) is marked as correct, though there appears to be a discrepancy.


Attaching official NTA answer key for reference.

Solution figure for CUET General Test 2025 29 May Shift 2 question 29 (Quantitative Reasoning) Solution figure for CUET General Test 2025 29 May Shift 2 question 29 (Quantitative Reasoning)

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