Simplify : 2 x [4 - \2 - (2-3) - (2+3)\ - 1] - 5 x [-3 - (3-2)] Option 1: 34 Option 2: 30 Option 3: 22 Option 4: -10

Answer: 30. Solution: Compute innermost brackets first. (2-3)=-1, (2+3)=5. Then \2-(-1)-5\ = -2. Next [4-(-2)-1] = 5, so 2 x 5 = 10. For the second part, (3-2)=1, [-3-1]=-4, so 5 x (-4) = -20. Final: 10 - (-20) = 30.

Quantitative Reasoning

Number System

Medium

Simplify : $2 \times [4 - \{2 - (2-3) - (2+3)\} - 1] - 5 \times [-3 - (3-2)]$

-10

✅ Correct Option: 2

Compute innermost brackets first. $(2-3)=-1$ , $(2+3)=5$ . Then $\{2-(-1)-5\} = -2$ . Next $[4-(-2)-1] = 5$ , so $2 \times 5 = 10$ . For the second part, $(3-2)=1$ , $[-3-1]=-4$ , so $5 \times (-4) = -20$ . Final: $10 - (-20) = 30$ .

2025: 23 May Shift 1

If x and y are negative integers, then which of the following statements is/are always true?

(A) x + y is positive integer.

(B) xy is positive integer.

Choose the correct answer from the options given below:

2025: 2 June Shift 2

How many numbers between -13 and 13 are multiples of 3 or 5?

2026: 26 May Shift 1

Find the number which is nearest to 3105 and is exactly divisible by 21.

2025: 20 May Shift 2

Match List-I with List-II

List-I	List-II
(A) The least number that must be subtracted from 2025 to get a number exactly divisible by 17	(I) 5
(B) The least number that must be added to $1057^{5}$ to get a number exactly divisible by 23	(II) 2
(C) Unit digit of $6^{15}-7^4$	(III) 0
(D) Find the product of any number and the 1st whole number	(IV) 1

Choose the correct answer from the options given below:

2025: 15 May Shift 1

Which of the following is/are prime numbers?

(A) 241

(B) 337

(D) 571

Choose the correct answer from the options given below:

2026: 20 May Shift 1

Match List-I with List-II

List-I	List-II
(A) The number $\pi$ is a/an	(I) whole number
(B) 0 is a/an	(II) complex number
(C) $\sqrt{-1}$ is a/an	(III) composite number
(D) 6 is a/an	(IV) irrational number

Choose the correct answer from the options given below:

Simplify : 2×[4−{2−(2−3)−(2+3)}−1]−5×[−3−(3−2)]2 \times [4 - \{2 - (2-3) - (2+3)\} - 1] - 5 \times [-3 - (3-2)]2×[4−{2−(2−3)−(2+3)}−1]−5×[−3−(3−2)]

Solution

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CUET General Test Past Year Questions (Topic-Wise)

Simplify : $2 \times [4 - \{2 - (2-3) - (2+3)\} - 1] - 5 \times [-3 - (3-2)]$