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The distance between points A (-5, 7) and B (-1, 3) is:

Solution

✅ Correct Option: 3

The distance between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is:

d=(x2−x1)2+(y2−y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}


Point A: (x1,y1)=(−5,7)(x_1, y_1) = (-5, 7)

Point B: (x2,y2)=(−1,3)(x_2, y_2) = (-1, 3)


d=(−1−(−5))2+(3−7)2d = \sqrt{(-1 - (-5))^2 + (3 - 7)^2}

d=(4)2+(−4)2d = \sqrt{(4)^2 + (-4)^2}

d=16+16d = \sqrt{16 + 16}

d=32d = \sqrt{32}


32=16×232 = 16 \times 2

32=16×2\sqrt{32} = \sqrt{16 \times 2}

32=16×2\sqrt{32} = \sqrt{16} \times \sqrt{2}

32=42\sqrt{32} = 4\sqrt{2}


Therefore, the distance between points A and B is 424\sqrt{2} units.

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