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Two numbers are in the ratio 3:5. If 3 is subtracted from the first number and 3 is added to the second number, the ratio becomes 1:3. The sum of the numbers is?

Solution

✅ Correct Option: 4

Two numbers are in the ratio 3:5.

Let the first number be 3x3x and the second number be 5x5x, where xx is a common multiplier.


After the changes:

  • First number becomes 3x−33x - 3
  • Second number becomes 5x+35x + 3
  • New ratio is 1:3

This gives us:

3x−35x+3=13\frac{3x - 3}{5x + 3} = \frac{1}{3}


3(3x−3)=1(5x+3)3(3x - 3) = 1(5x + 3)

9x−9=5x+39x - 9 = 5x + 3

9x−5x=3+99x - 5x = 3 + 9

4x=124x = 12

x=3x = 3


The actual numbers are:

First number =3x=3×3=9= 3x = 3 \times 3 = 9

Second number =5x=5×3=15= 5x = 5 \times 3 = 15


Sum =9+15=24= 9 + 15 = 24

Therefore, the sum of the numbers is 24.

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