Arithmetic

Central Tendency

Medium

The median of a set of 11 distinct observations is 22.5. If each of the largest 5 observations of the set is increased by 5, then the median of the new set

is decreased by 5.

is increased by 5.

remains the same as that of the original set.

two times the original median.

✅ Correct Option: 3

For a set of 11 distinct observations arranged in order, the median is the 6th observation (with 5 observations before it and 5 after it).

The original set in order:

Position: 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th

The 6th observation $= 22.5$ (the median)

The largest 5 observations are at positions 7th, 8th, 9th, 10th, and 11th.

When each of these 5 observations is increased by 5, the observations at positions 1st through 6th remain unchanged.

After the modification:

Positions 1-6: unchanged

Positions 7-11: each increased by 5

The median is still the 6th observation, which remains $22.5$ .

The median of the new set $= 22.5$

The median remains the same as the original set because only observations after the median position were modified, leaving the 6th position unchanged.

Therefore, the correct answer is option 3: remains the same as that of the original set.

2026: 26 May Shift 1

The median of frequency distribution is:

Class :	0 – 25	25 – 50	50 – 75	75 – 100
Frequency :	23	32	15	12

2023: 5 June Shift 2

In a particular week, the average earning per day of a plumber from Monday to Wednesday remained Rs. 580 and that from Thursday to Saturday it was Rs. 612. If the average earning for the whole week was Rs. 675, then how much did he earn on Sunday ?

2025: 22 May Shift 2

The average of marks of 15 papers is 45. The average of marks of the first 8 papers is 48 and that of the last 8 papers is 40. The marks of the eight paper will be:

2025: 3 June Shift 1

In a class, the number of students who scored 61 or more marks is 30 and there are almost 39 students who have scored below 61 marks.

If the average marks of the class is 48, then determine that what is the largest possible average marks of students who have scored below 61 marks?

2026: 12 May Shift 1

The median of the following frequency distribution is 52. If the total frequency is 50, the values of x and y are:

Class Interval	Class Frequency
0-10	1
10-20	3
20-30	x
30-40	6
40-50	5
50-60	8
60-70	y
70-80	7
80-90	5
90-100	3

2026: 18 May Shift 2

The mean of 5 numbers is 15. If one more number is included, the mean of the 6 numbers becomes 17. Find the included number.

The median of a set of 11 distinct observations is 22.5. If each of the largest 5 observations of the set is increased by 5, then the median of the new set

Solution

Related questions:

Keyboard Shortcuts

CUET General Test Past Year Questions (Topic-Wise)