How much an angular distance will be covered by the minute hand of a correct clock in a period of 1 h 45 min?

The minute hand completes one full circle in 60 minutes.

One full circle = 360°

The minute hand moves at a rate of:

$\dfrac{360°}{60 \text{ minutes}} = 6°$ per minute

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Convert 1 hour 45 minutes to minutes:

$1 \text{ hour} = 60 \text{ minutes}$

Total time $= 60 + 45 = 105$ minutes

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Angular distance covered = Rate $\times$ Time

Angular distance $= 6° \times 105$

$= 630°$

Therefore, the minute hand covers an angular distance of 630°.