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Arrange the simple interest of the following cases in decreasing order-

(A) The simple interest on Rs 6600 at 5% per annum for 2 yrs.

(B) The simple interest on Rs 200 at 6% per annum for 5 yrs.

(C) The simple interest on Rs 840 at 5% per annum for 4 yrs.

(D) The simple interest on Rs 5000 at 12% per annum for 2 yrs.

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

Simple Interest is calculated using:

SI=P×R×T100SI = \dfrac{P \times R \times T}{100}

where PP = Principal, RR = Rate of interest per year (%), TT = Time (years)


For case (A): P=6600P = 6600, R=5R = 5, T=2T = 2

SI=6600×5×2100SI = \dfrac{6600 \times 5 \times 2}{100}

SI=66000100SI = \dfrac{66000}{100}

SI=660SI = 660


For case (B): P=200P = 200, R=6R = 6, T=5T = 5

SI=200×6×5100SI = \dfrac{200 \times 6 \times 5}{100}

SI=6000100SI = \dfrac{6000}{100}

SI=60SI = 60


For case (C): P=840P = 840, R=5R = 5, T=4T = 4

SI=840×5×4100SI = \dfrac{840 \times 5 \times 4}{100}

SI=16800100SI = \dfrac{16800}{100}

SI=168SI = 168


For case (D): P=5000P = 5000, R=12R = 12, T=2T = 2

SI=5000×12×2100SI = \dfrac{5000 \times 12 \times 2}{100}

SI=120000100SI = \dfrac{120000}{100}

SI=1200SI = 1200


Comparing the simple interests:

(D) = Rs 1200

(A) = Rs 660

(C) = Rs 168

(B) = Rs 60

Therefore, the decreasing order is: (D), (A), (C), (B)

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