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Suppose we throw a dice once. Then, which one of the following is/are correct?

(A) The probability of getting a number greater than 4 is 13\frac{1}{3}

(B) The probability of getting a number greater than or equal to 4 is 13\frac{1}{3}

(C) The probability of getting a number less than or equal to 3 is 12\frac{1}{2}

(D) The probability of getting a number less than or equal to 6 is 1.

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

When throwing a standard dice once, there are 6 possible outcomes: 1, 2, 3, 4, 5, 6

Probability =Number of favorable outcomesTotal possible outcomes=Favorable outcomes6= \dfrac{\text{Number of favorable outcomes}}{\text{Total possible outcomes}} = \dfrac{\text{Favorable outcomes}}{6}


(A) Probability of getting a number greater than 4 is 13\frac{1}{3}

Numbers greater than 4: 5, 6

Number of favorable outcomes =2= 2

Probability =26= \dfrac{2}{6}

Probability =13= \dfrac{1}{3}

Statement (A) is correct.


(B) Probability of getting a number greater than or equal to 4 is 13\frac{1}{3}

Numbers greater than or equal to 4: 4, 5, 6

Number of favorable outcomes =3= 3

Probability =36= \dfrac{3}{6}

Probability =12= \dfrac{1}{2}

Statement (B) is incorrect.


(C) Probability of getting a number less than or equal to 3 is 12\frac{1}{2}

Numbers less than or equal to 3: 1, 2, 3

Number of favorable outcomes =3= 3

Probability =36= \dfrac{3}{6}

Probability =12= \dfrac{1}{2}

Statement (C) is correct.


(D) Probability of getting a number less than or equal to 6 is 1

Numbers less than or equal to 6: 1, 2, 3, 4, 5, 6

Number of favorable outcomes =6= 6

Probability =66= \dfrac{6}{6}

Probability =1= 1

Statement (D) is correct.


Therefore, statements (A), (C), and (D) are correct.

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