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An integer number is chosen at random from the first 100 integers. What is the probability that the chosen number is a perfect cube?

Solution

✅ Correct Option: 4

The first 100 integers are: 1, 2, 3, 4, ..., 100

Total integers = 100


A perfect cube is a number that can be expressed as n3n^3 where nn is an integer.

The perfect cubes from 1 to 100:

13=11^3 = 1

23=82^3 = 8

33=273^3 = 27

43=644^3 = 64

53=1255^3 = 125 (exceeds 100)

Perfect cubes from 1 to 100: {1, 8, 27, 64}

Total perfect cubes = 4


Probability = Number of favorable outcomesTotal number of outcomes\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}

Probability = 4100\dfrac{4}{100}

Probability = 125\dfrac{1}{25}


Therefore, the probability that a randomly chosen number from the first 100 integers is a perfect cube is 125\dfrac{1}{25}.

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