Logical Reasoning

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A girl walks 20 meters towards North. Then, turning to her left, she walks 50 meters. Then, turning to her right, she walks 40 metres. Again, she turns to her right and walks 50 metres. How far is she from her initial position?

60 metres

50 metres

20 metres

40 metres

✅ Correct Option: 1

Let the initial position be at the origin with coordinates $(0, 0)$ .

The girl walks 20 meters North:

Position: $(0, 20)$

Direction: North

She turns left (now facing West) and walks 50 meters:

Position: $(0 - 50, 20) = (-50, 20)$

Direction: West

She turns right (now facing North) and walks 40 meters:

Position: $(-50, 20 + 40) = (-50, 60)$

Direction: North

She turns right again (now facing East) and walks 50 meters:

Position: $(-50 + 50, 60) = (0, 60)$

Direction: East

The distance from her initial position $(0, 0)$ to final position $(0, 60)$ is:

$d = \sqrt{(0-0)^2 + (60-0)^2}$

$d = \sqrt{0 + 3600}$

$d = \sqrt{3600}$

$d = 60$ meters

Therefore, she is 60 meters from her initial position.

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Starting from point P, Sunil walked 30 m towards South. He turned to his left and walked 40 m. Then, he again turned to his left and walked 30 m. Turning again to his left he walks 15 m and stops there at point N. How far is Sunil from starting point P ?

A girl walks 20 meters towards North. Then, turning to her left, she walks 50 meters. Then, turning to her right, she walks 40 metres. Again, she turns to her right and walks 50 metres. How far is she from her initial position?

Solution

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