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CUET General Test 2025 PYQs13 May Shift 1. Free, no login required.

Arithmetic

past year questions, CUET General Test 2025 13 May Shift 1

Central Tendency

past year questions, Arithmetic, CUET General Test 2025 13 May Shift 1

Medium

The marks out of 50 obtained by 100 students in a test are given below as:

Marks obtained2025282933384243
Number of students620242815421

Find the value of the (3 mode - 2 median).

Solution

✅ Correct Option: 3

To find the value of 3×Mode−2×Median3 \times \text{Mode} - 2 \times \text{Median}, both the mode and median need to be determined.

The mode is the marks obtained by the highest number of students.

Marks2025282933384243
Students620242815421

29 marks has the highest frequency of 28 students.

Mode =29= 29

Total students =100= 100 (even number)

For an even number of observations, the median is the average of the n2\frac{n}{2}th and (n2+1)(\frac{n}{2} + 1)th values.

Median =50th value+51st value2= \frac{50\text{th value} + 51\text{st value}}{2}

Finding the cumulative frequency:

MarksStudentsCumulative Frequency
2066
252026
282450
292878
331593
38497
42299
431100

The 50th student scored 28 marks.

The 51st student scored 29 marks.

Median =28+292= \frac{28 + 29}{2}

Median =572= \frac{57}{2}

Median =28.5= 28.5

3×Mode−2×Median3 \times \text{Mode} - 2 \times \text{Median}

=3×29−2×28.5= 3 \times 29 - 2 \times 28.5

=87−57= 87 - 57

=30= 30

Therefore, the value of (3 mode−2 median)=30(3 \text{ mode} - 2 \text{ median}) = 30

Related questions:

2025: 28 May Shift 2

In the first 9 matches of a cricket tournament, the wickets taken by Jumpo are as follows:

3 2 0 1 3 0 5 1 4

Find the median of the number of wickets taken by Jumpo?

2025: 19 May Shift 2

In a moderately asymmetrical distribution, the mode and mean are 31.5 and 34.5, respectively. Calculate the median:

2022: 23 Aug Shift 1

The average of first 99 positive integers is:

2022: 24 Aug Shift 1

If the average of 3, 8, 9 and x is 8. Then, what is the value of x ?

2025: 20 May Shift 2

The age distribution of 40 children is as follows

Age (in yr.)5 - 66 - 77 - 88 - 99 - 1010 - 11
No. of children4791262

Consider the following statements in respect of the above frequency distribution.

(A) The median of the age distribution is 7 yr.

(B) 70% of the children are in the age group 6-9 yr.

(C) The modal class of the children is 8-9 yr.

Which of the above statements are true?

Choose the correct answer from the options given below:

2023: 21 May Shift 1

If the median of x5,x,x4,x2\frac{x}{5}, x, \frac{x}{4}, \frac{x}{2} and x3\frac{x}{3} (where x>0x > 0) is 8, then the value of xx will be

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