Geometry

Miscellaneous

Medium

If Q(0, 1) is equidistant from P(5, -3) and R(x, 6), find the values of x.

± 1

± 4

± 6

✅ Correct Option: 3

$QP^2 = (5-0)^2 + (-3-1)^2 = 25 + 16 = 41$ .

$QR^2 = x^2 + (6-1)^2 = x^2 + 25$ .

Setting them equal: $x^2 + 25 = 41 \Rightarrow x^2 = 16 \Rightarrow x = \pm 4$ .

2025: 19 May Shift 2

If two vertices of a triangle are (5, 4) and (-2, 4) and centroid is (5,6), then third vertex is:

2023: 21 May Shift 1

The point (-2, 3) lies in which quadrant?

2026: 30 May Shift 1

If A is area of regular hexagon of side 2 cm, then value of 3A (in cm $^2$ ), is:

2026: 12 May Shift 1

If abscissa of a point is 2 and the ordinate is 5, then the coordinates of the point located in xy plane is:

2025: 20 May Shift 1

If area of a square is 44 cm², find the area of the circle formed by the same perimeter.

2022: 6 Aug Shift 1

Area covered by the figure is:

Solution