Logical Reasoning

Sequence & Series

Medium

In an A.P., the product of the first term and the second term is 120 and the product of the second term and the third term is 168. Find the tenth term of the A.P. when common difference d > 0.

132

✅ Correct Option: 3

Let the three terms be $a$ , $a+d$ , $a+2d$ . Given $a(a+d)=120$ and $(a+d)(a+2d)=168$ . Testing $a=10, d=2$ : $10\times 12=120$ and $12\times 14=168$ . Both hold and $d>0$ . Then $a_{10}=a+9d=10+18=28$ .

2025: 14 May Shift 2

Consider the alphabet series as given below and answer the question that follows:

A B C D E F G H I J K L M N O P Q R S T U V W X Y Z

Now, if all the vowels are removed from the given series, then which alphabet will be the seventh to the right of the fifth alphabet from the left?

2022: 26 Aug Shift 1

Complete the series: 20, 24, 30, 32, 38, 42,__________.

2026: 21 May Shift 1

What will be the 21st term of the series given below ?

3, 9, 15, ........

2026: 30 May Shift 1

Find the next term (?) in the given series:

1, 3, 6, 10, 15, ?, ...

2025: 13 May Shift 1

Find the term which doesn't fit into the series given below:

H4Q, K10N, N20K, Q43H, T90E

2023: 28 May Shift 1

What is missing term in given series ?

In an A.P., the product of the first term and the second term is 120 and the product of the second term and the third term is 168. Find the tenth term of the A.P. when common difference d > 0.

Solution

Related questions:

Keyboard Shortcuts

CUET General Test Past Year Questions (Topic-Wise)