In a ABC right angled at A, if ABC = 60^ and AC = 4 units, then length of BC (in units) is : Option 1: √3 Option 2: 8/√3 Option 3: 8 Option 4: 4/√3

Answer: 8/√3. Solution: Right angle at A, B=60^. AC is opposite to B, so 60^=AC/BC. Thus √3/2=4/BC, giving BC=8/√3.

Geometry

Trigonometry

Medium

In a $\Delta ABC$ right angled at A, if $\angle ABC = 60^\circ$ and AC = 4 units, then length of BC (in units) is :

$\sqrt{3}$

$\frac{8}{\sqrt{3}}$

$\frac{4}{\sqrt{3}}$

✅ Correct Option: 2

Right angle at A, $\angle B=60^\circ$ . AC is opposite to B, so $\sin 60^\circ=\frac{AC}{BC}$ . Thus $\frac{\sqrt{3}}{2}=\frac{4}{BC}$ , giving $BC=\frac{8}{\sqrt{3}}$ .

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In a ΔABC\Delta ABCΔABC right angled at A, if ∠ABC=60∘\angle ABC = 60^\circ∠ABC=60∘ and AC = 4 units, then length of BC (in units) is :

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In a $\Delta ABC$ right angled at A, if $\angle ABC = 60^\circ$ and AC = 4 units, then length of BC (in units) is :