Skip to main contentSkip to solution

Solution

Correct Option: 3

Divisible by 8: last 3 digits '64B' divisible by 8, so B=0 or 8. Divisible by 9: sum 4+8+5+A+6+4+B=27+A+B4+8+5+A+6+4+B=27+A+B divisible by 9, so A+BA+B is 0, 9, or 18. With B=8: A+B=9A+B=9 means A=1, or A+B=18A+B=18 means A=10 (invalid). With B=0: A+B=9A+B=9 means A=9. Maximum A+B=9A+B=9.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question