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From a point 60 m away from the foot of a building, the angle of elevation of the top of the building is 30°. What is the height of the building?

Solution

✅ Correct Option: 1

Height =60×tan⁡30∘=603=203= 60 \times \tan 30^\circ = \dfrac{60}{\sqrt3} = 20\sqrt3 m.

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