Skip to main contentSkip to solution

A pole casts a shadow of length 232\sqrt{3} meter on the ground when the sun's elevation is 60°. The height of the pole is:

Solution

✅ Correct Option: 3

tan⁡60∘=h23\tan 60^\circ = \dfrac{h}{2\sqrt{3}}, and tan⁡60∘=3\tan 60^\circ = \sqrt{3}.

So h=3×23=6h = \sqrt{3} \times 2\sqrt{3} = 6 metres.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question