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Two men P and Q start together from place A at 3 km/h and 3.75 km/h respectively for place B. Q reaches half an hour before P. What is the distance that each one has covered ?

Solution

Correct Option: 3

Let distance = dd km.

Time difference: d3d3.75=12\frac{d}{3} - \frac{d}{3.75} = \frac{1}{2}.

d(13415)=12d \left(\frac{1}{3} - \frac{4}{15}\right) = \frac{1}{2}, so d×115=12d \times \frac{1}{15} = \frac{1}{2}.

Therefore d=7.5d = 7.5 km.

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