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A train passes a 200 m long platform in 40 seconds and a man standing on the platform in 25 seconds. The speed of the train (km/hr) is:

Solution

✅ Correct Option: 3

When a train passes a man standing on a platform, it travels a distance equal to its own length. When a train passes a platform completely, it travels a distance equal to its own length plus the platform length.

The difference in distance covered is equal to the platform length.


Time to pass man = 25 seconds

Time to pass platform = 40 seconds

Extra time taken = 40 - 25 = 15 seconds

This extra time is required to cover the platform length of 200 m.

Speed = DistanceTime\dfrac{\text{Distance}}{\text{Time}}

Speed = 20015\dfrac{200}{15} m/s


To convert m/s to km/hr, multiply by 185\dfrac{18}{5}:

Speed = 20015×185\dfrac{200}{15} \times \dfrac{18}{5}

=200×1815×5= \dfrac{200 \times 18}{15 \times 5}

=360075= \dfrac{3600}{75}

=48= 48 km/hr


Therefore, the speed of the train is 48 km/hr.

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