Skip to main contentSkip to solution

Find the value of 6+6+6+6+\sqrt{6 + \sqrt{6 + \sqrt{6 + \sqrt{6 + \ldots}}}}.

Solution

Correct Option: 1

Let x=6+6+x = \sqrt{6 + \sqrt{6 + \ldots}}. Then x2=6+xx^2 = 6 + x.

x2x6=0x^2 - x - 6 = 0, so (x3)(x+2)=0(x-3)(x+2) = 0.

Taking the positive root, x=3x = 3.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question