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The value of (xy)2a3b×(xy)3b4c×(xy)4c2a\left(\frac{x}{y}\right)^{2a-3b} \times \left(\frac{x}{y}\right)^{3b-4c} \times \left(\frac{x}{y}\right)^{4c-2a}

Solution

Correct Option: 2

Adding the exponents: (2a3b)+(3b4c)+(4c2a)=0(2a-3b) + (3b-4c) + (4c-2a) = 0. Therefore the expression equals (xy)0=1\left(\frac{x}{y}\right)^0 = 1.

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