Consider the following statements:

(A) The unit's digit in the product of (5236 x 6231) is 1.

(B) The digit in the unit's place for the product 31 x 32 x 33 x 34 x ....x 49 is 0.

(C) The sum of the face values of 7 and 4 in 8175349 is 11.

(D) The sum of the place values of 3 in 3935 is 6.

Choose the correct answer from the options given below:

Statement (A): The unit's digit in the product of (5236 × 6231) is 1.

To find the unit's digit of a product, multiply the unit's digits:

Unit's digit of 5236 = 6

Unit's digit of 6231 = 1

Unit's digit of their product = 6 × 1 = 6

The unit's digit is 6, not 1. Statement (A) is false.

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Statement (B): The digit in the unit's place for the product 31 × 32 × 33 × 34 × ... × 49 is 0.

The product includes all numbers from 31 to 49.

The number 40 is in this range, and 40 = 4 × 10.

Any number multiplied by 10 (or a multiple of 10) will have a unit's digit of 0.

The unit's digit is 0. Statement (B) is true.

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Statement (C): The sum of the face values of 7 and 4 in 8175349 is 11.

Face value is the digit itself, regardless of position.

In the number 8175349:

Face value of 7 = 7

Face value of 4 = 4

Sum = 7 + 4 = 11

Statement (C) is true.

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Statement (D): The sum of the place values of 3 in 3935 is 6.

Place value is the digit multiplied by its position value.

In the number 3935, the digit 3 appears twice:

The 3 in the thousands place: 3 × 1000 = 3000

The 3 in the tens place: 3 × 10 = 30

Sum of place values = 3000 + 30 = 3030

The sum is 3030, not 6. Statement (D) is false.

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Statement (B) is true.

Statement (C) is true.

Statement (A) is false.

Statement (D) is false.

Therefore, only (B) and (C) are correct.