IPMAT IndoreAlgebra > MediumEntered answer:✅ Correct Answer: 960Related questions:IPMAT Indore 2019Assume that all positive integers are written down consecutively from left to right as in 1234567891011...... The 6389th digit in this sequence isIPMAT Indore 2019If (1+x−2x2)6=A0+∑r=112Arxr(1 + x - 2x^2)^6 = A_0 + \sum_{r=1}^{12} A_r x^r(1+x−2x2)6=A0+∑r=112Arxr, then the value of A2+A4+A6+⋯+A12A_2 + A_4 + A_6 + \cdots + A_{12}A2+A4+A6+⋯+A12 isIPMAT Indore 2019There are numbers a1,a2,a3,…,ana_1, a_2, a_3, \ldots, a_na1,a2,a3,…,an each of them being +1+1+1 or −1-1−1. If it is known that a1a2+a2a3+a3a4+…an−1an+ana1=0a_1 a_2 + a_2 a_3 + a_3 a_4 + \ldots a_{n-1} a_n + a_n a_1 = 0a1a2+a2a3+a3a4+…an−1an+ana1=0 then