IPMAT Indore - The numbers -16,2^x+3-2^2 x-1-16,2^2 x-1+16 are in an arithmetic progression. Then x equals ________. | PYQs + Solutions

IPMAT Indore

Algebra

Medium

Entered answer:

✅ Correct Answer: 3

Related questions:

IPMAT Indore 2019

Assume that all positive integers are written down consecutively from left to right as in 1234567891011...... The 6389th digit in this sequence is

IPMAT Indore 2019

There are numbers $a_1, a_2, a_3, \ldots, a_n$ each of them being $+1$ or $-1$ . If it is known that $a_1 a_2 + a_2 a_3 + a_3 a_4 + \ldots a_{n-1} a_n + a_n a_1 = 0$ then

IPMAT Indore 2021

It is given that the sequence { $x_n$ } satisfies $x_1 = 0, x_{n+1} = x_n + 1 + 2√(1+x_n)$ for $n = 1,2,...$ Then $x_{31}$ is _______

IPMAT Indore (SA) PYQs

Keyboard Shortcuts