IPMAT Indore - The numbers -16,2^x+3-2^2 x-1-16,2^2 x-1+16 are in an arithmetic progression. Then x equals ________. | PYQs + Solutions

IPMAT Indore

Algebra

Medium

Entered answer:

✅ Correct Answer: 3

Related questions:

IPMAT Indore 2021

It is given that the sequence { $x_n$ } satisfies $x_1 = 0, x_{n+1} = x_n + 1 + 2√(1+x_n)$ for $n = 1,2,...$ Then $x_{31}$ is _______

IPMAT Indore 2019

Let $\alpha, \beta$ be the roots of $x^2 - x + p = 0$ and $\gamma, \delta$ be the roots of $x^2 - 4x + q = 0$ where p and q are integers. If $\alpha, \beta, \gamma, \delta$ are in geometric progression then $p + q$ is

IPMAT Indore 2023

If $f(n)= 1 + 2 + 3 +\cdots+(n+1)$ and $g(n)= \sum_{k=1}^{k=n} \dfrac{1}{f(k)}$ , then the least value of $n$ for which $g(n)$ exceeds the value $\dfrac{99}{100}$ is:

IPMAT Indore (SA) PYQs

Keyboard Shortcuts