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The HCF and LCM of two numbers x\mathrm{x} and y\mathrm{y} are respectively 6 and 210 .

If x+y=72x+y=72, then 1x+1y\frac{1}{x}+\frac{1}{y} is equal to :

Solution

Correct Option: 4
  1. Given:
  • HCF(x,yx,y) = 66
    • LCM(x,yx,y) = 210210
    • x+y=72x + y = 72
  1. We know that for any two numbers:
  • x×y=HCF×LCMx × y = \text{HCF} × \text{LCM}
    • Therefore, x×y=6×210=1260x × y = 6 × 210 = 1260
  1. Now we have two equations:
  • x+y=72x + y = 72
    • x×y=1260x × y = 1260
  1. To find 1x+1y\frac{1}{x} + \frac{1}{y}:
  • 1x+1y=y+xxy\frac{1}{x} + \frac{1}{y} = \frac{y + x}{xy}
    • = 721260\frac{72}{1260}
    • = 721260\frac{72}{1260}
    • = 36630\frac{36}{630}
    • = 235\frac{2}{35}

Therefore, 1x+1y=235\frac{1}{x} + \frac{1}{y} = \frac{2}{35}

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