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The points (2,2),(6,3)(2,2),(6,3) and (4,11)(4,11) are vertices of :

Solution

Correct Option: 3

Let's identify the triangle with points (2,2), (6,3), and (4,11).

Side lengths using d=(x2x1)2+(y2y1)2d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}:

AB = (62)2+(32)2\sqrt{(6-2)^2 + (3-2)^2} = 17\sqrt{17}

BC = (46)2+(113)2\sqrt{(4-6)^2 + (11-3)^2} = 68\sqrt{68}

AC = (42)2+(112)2\sqrt{(4-2)^2 + (11-2)^2} = 85\sqrt{85}

Checking for right angle using Pythagorean theorem:

AC² = AB² + BC²

85=17+6885 = 17 + 68

Properties:

  1. All sides different lengths: 17\sqrt{17}68\sqrt{68}85\sqrt{85} → Scalene
  2. AC² = AB² + BC² → Right-angled at B

Therefore, this is both a right-angled and scalene triangle. NTA made an error. Marks were awarded for both the options 3 and 4.

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