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The sides of four triangles are given below. Which of them forms a right triangle ?

(A) 20 cm,22 cm,24 cm20 \mathrm{~cm}, 22 \mathrm{~cm}, 24 \mathrm{~cm}

(B) 15 cm,32 cm,37 cm15 \mathrm{~cm}, 32 \mathrm{~cm}, 37 \mathrm{~cm}

(C) 11 cm,60 cm,61 cm11 \mathrm{~cm}, 60 \mathrm{~cm}, 61 \mathrm{~cm}

(D) 6 cm,8 cm,10 cm6 \mathrm{~cm}, 8 \mathrm{~cm}, 10 \mathrm{~cm}

Solution

✅ Correct Option: 4

Check each triangle using the Pythagorean theorem (a2+b2=c2)(a^2 + b^2 = c^2).

For (A) 20 cm, 22 cm, 24 cm:

202+222=400+484=88420^2 + 22^2 = 400 + 484 = 884

242=57624^2 = 576

884≠576884 \neq 576 → Not a right triangle

\hspace{5cm}

For (B) 15 cm, 32 cm, 37 cm:

152+322=225+1024=124915^2 + 32^2 = 225 + 1024 = 1249

372=136937^2 = 1369

1249≠13691249 \neq 1369 → Not a right triangle

\hspace{5cm}

For (C) 11 cm, 60 cm, 61 cm:

112+602=121+3600=372111^2 + 60^2 = 121 + 3600 = 3721

612=372161^2 = 3721

3721=37213721 = 3721 → This is a right triangle!

\hspace{5cm}

For (D) 6 cm, 8 cm, 10 cm:

62+82=36+64=1006^2 + 8^2 = 36 + 64 = 100

102=10010^2 = 100

100=100100 = 100 → This is a right triangle!

\hspace{3cm}

Both triangles (C) and (D) satisfy the Pythagorean theorem.

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