The sides of four triangles are given below. Which of them forms a right triangle ? (A) $20 \mathrm{~cm}, 22 \mathrm{~cm}, 24 \mathrm{~cm}$ (B) $15 \mathrm{~cm}, 32 \mathrm{~cm}, 37 \mathrm{~cm}$ (C) $11 \mathrm{~cm}, 60 \mathrm{~cm}, 61 \mathrm{~cm}$ (D) $6 \mathrm{~cm}, 8 \mathrm{~cm}, 10 \mathrm{~cm}$
Solution
✅ Correct Option: 4
Check each triangle using the Pythagorean theorem $(a^2 + b^2 = c^2)$. For (A) 20 cm, 22 cm, 24 cm: $20^2 + 22^2 = 400 + 484 = 884$ $24^2 = 576$ $884 \neq 576$ → Not a right triangle $\hspace{5cm}$ For (B) 15 cm, 32 cm, 37 cm: $15^2 + 32^2 = 225 + 1024 = 1249$ $37^2 = 1369$ $1249 \neq 1369$ → Not a right triangle $\hspace{5cm}$ For (C) 11 cm, 60 cm, 61 cm: $11^2 + 60^2 = 121 + 3600 = 3721$ $61^2 = 3721$ $3721 = 3721$ → This is a right triangle! $\hspace{5cm}$ For (D) 6 cm, 8 cm, 10 cm: $6^2 + 8^2 = 36 + 64 = 100$ $10^2 = 100$ $100 = 100$ → This is a right triangle! $\hspace{3cm}$ Both triangles (C) and (D) satisfy the Pythagorean theorem.
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