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A candidate scoring x%x \% marks in an examination fails by ' aa ' marks while another candidate who scores y%y \% marks, gets ' bb ' marks more than the minimum required pass marks. What is the maximum marks for the examination ?

Solution

✅ Correct Option: 3
  1. Let's say maximum marks is MM
  • Then x%x\% of M=xM100M = \frac{xM}{100}
  1. Let pass marks be PP
  1. For first candidate:
  • Score = xM100\frac{xM}{100}
    • Fails by aa marks
    • Therefore: xM100=P−a\frac{xM}{100} = P - a
  1. For second candidate:
  • Score = yM100\frac{yM}{100}
    • Exceeds by bb marks
    • Therefore: yM100=P+b\frac{yM}{100} = P + b
  1. From equations:

xM100=P−a\frac{xM}{100} = P - a ...(1)

yM100=P+b\frac{yM}{100} = P + b ...(2)

  1. Subtracting (1) from (2):

(y−x)M100=a+b\frac{(y-x)M}{100} = a+b

M=100(a+b)y−xM = \frac{100(a+b)}{y-x}

Therefore, maximum marks = 100(a+b)y−x\frac{100(a+b)}{y-x}

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