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The number of ways in which coins of denominations of rupees 2, 5 and, 10 can be combined to make a value of rupees 50 is

Solution

Correct Option: 2

Let aa, bb, cc be the number of Rs 22, Rs 55, and Rs 1010 coins.

2a+5b+10c=502a + 5b + 10c = 50


Fix cc and count valid (a,b)(a, b) pairs. The equation becomes:

2a+5b=5010c2a + 5b = 50 - 10c

The right side is even, so 5b5b must be even, meaning bb must be even.


For each value of cc, list even values of bb such that 5b5010c5b \leq 50 - 10c:

c=0c = 0: b{0,2,4,6,8,10}b \in \{0, 2, 4, 6, 8, 10\} gives 66 ways

c=1c = 1: b{0,2,4,6,8}b \in \{0, 2, 4, 6, 8\} gives 55 ways

c=2c = 2: b{0,2,4,6}b \in \{0, 2, 4, 6\} gives 44 ways

c=3c = 3: b{0,2,4}b \in \{0, 2, 4\} gives 33 ways

c=4c = 4: b{0,2}b \in \{0, 2\} gives 22 ways

c=5c = 5: b=0b = 0 gives 11 way


Total =6+5+4+3+2+1=21= 6 + 5 + 4 + 3 + 2 + 1 = 21

Answer =21= 21

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