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The number of ways in which coins of denominations of rupees 2, 5 and, 10 can be combined to make a value of rupees 50 is

Solution

✅ Correct Option: 2

Let aa, bb, cc be the number of Rs 22, Rs 55, and Rs 1010 coins.

2a+5b+10c=502a + 5b + 10c = 50


Fix cc and count valid (a,b)(a, b) pairs. The equation becomes:

2a+5b=50−10c2a + 5b = 50 - 10c

The right side is even, so 5b5b must be even, meaning bb must be even.


For each value of cc, list even values of bb such that 5b≤50−10c5b \leq 50 - 10c:

c=0c = 0: b∈{0,2,4,6,8,10}b \in \{0, 2, 4, 6, 8, 10\} gives 66 ways

c=1c = 1: b∈{0,2,4,6,8}b \in \{0, 2, 4, 6, 8\} gives 55 ways

c=2c = 2: b∈{0,2,4,6}b \in \{0, 2, 4, 6\} gives 44 ways

c=3c = 3: b∈{0,2,4}b \in \{0, 2, 4\} gives 33 ways

c=4c = 4: b∈{0,2}b \in \{0, 2\} gives 22 ways

c=5c = 5: b=0b = 0 gives 11 way


Total =6+5+4+3+2+1=21= 6 + 5 + 4 + 3 + 2 + 1 = 21

Answer =21= 21

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