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A nutritionist is designing a daily diet plan of a person using five food items: Milk, Spinach, Almonds, Oats, and Rice. The Minimum Daily Requirement (MDR) of the nutrients Calcium, Iron and Protein should be 1100 mg, 15 mg, and 40 g, respectively. The following table gives nutrient content per serving of each food item:

Food itemCalcium (mg)Iron (mg)Protein (g)
Milk30008
Spinach9063
Almonds21046
Oats12035
Rice5014

Each serving provides a certain percentage of the MDR. For example, one serving of milk satisfies 20% of MDR of Protein. Further, the number of servings of any food item should be a whole number.

When one serving of each of the five items is included in the diet plan, the nutrient with the least percentage of MDR satisfied is

Solution

Correct Option: 1

One serving of each of the five foods gives:

Calcium =300+90+210+120+50=770= 300 + 90 + 210 + 120 + 50 = 770 mg

Iron =0+6+4+3+1=14= 0 + 6 + 4 + 3 + 1 = 14 mg

Protein =8+3+6+5+4=26= 8 + 3 + 6 + 5 + 4 = 26 g


Convert each total to a percentage of its MDR.


Calcium:

7701100×100=70%\dfrac{770}{1100} \times 100 = 70\%


Iron:

1415×10093.3%\dfrac{14}{15} \times 100 \approx 93.3\%


Protein:

2640×100=65%\dfrac{26}{40} \times 100 = 65\%


The smallest of these is 65%65\%, for protein.

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