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The state of Panchagarh has 5 cities, whose population contributions are shown in the pie chart below. Figure for UGAT Bangalore 2025 Actual Paper QA question 15 (Data Interpretation) The bar graph below shows the percentage of males in each city of Panchagarh in 2016. These percentages do not change over time. Figure for UGAT Bangalore 2025 Actual Paper QA question 15 (Data Interpretation)

Assume the population of city R was 96000 in 2016. Then, in percentage terms, by how much was it more than the male population of city T?

Solution

✅ Correct Option: 3

City R contributes 25% of the state, so the state total follows from R:

State=960000.25=384000\text{State} = \frac{96000}{0.25} = 384000

QuantityWorkingValue
Population of T0.12×3840000.12 \times 38400046,08046{,}080
Male population of T0.60×460800.60 \times 4608027,64827{,}648

Excess of R over the male population of T: 96000−27648=6835296000 - 27648 = 68352

As a percentage of the male population of T: 6835227648×100=247.2%\frac{68352}{27648} \times 100 = 247.2\%

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