IIM Bangalore (UGAT) - Arithmetic - Mean, Median & Mode | Free Questions

Q1:

PYP 2025

Arithmetic > Mean, Median & Mode

Medium

A bag consists of tokens whose labels are selected from all of the first $n$ even natural numbers. The frequency of each label equals half the label itself. Then the variance of all the labels the bag is

$\frac{2(2n + 1)}{3}$

$\frac{2n^2 + 2n - 4}{9}$

$\frac{n^2 + 2n + 5}{9}$

$\frac{2n^2 + n - 2}{9}$

Correct Answer

Option 2

Correct Answer

Explanation →

Q2:

Sample Paper

Arithmetic > Mean, Median & Mode

Hard

We have a bag of tokens. Each token has a label $m$ chosen from the squares of the first $n$ natural numbers, with frequency $\sqrt{m}$. What is the arithmetic mean of the labels?

$\frac{n(n+1)}{2}$

$\frac{(2n+1)}{3}$

$\left(\frac{n(n+1)}{2}\right)^2$

$n\left(\frac{(n+1)}{2}\right)^2$

Correct Answer

Option 1

Correct Answer

Explanation →

Q3:

Sample Paper

Arithmetic > Mean, Median & Mode

Medium

Arun scored 25, 13, 12 and 22 points in the $6^{\text{th}}$, $7^{\text{th}}$, $8^{\text{th}}$ and $9^{\text{th}}$ basketball games, respectively. His points-per game average was higher after nine games than it was after the first five games. If his average after ten games was greater than 19, the least number of points that he could have scored in the $10^{\text{th}}$ game, was

Correct Answer

Option 1

Correct Answer

Explanation →

IIM Bangalore (UGAT) Arithmetic > Mean, Median & Mode PYQs

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