Q1:PYP 2025Algebra > EasyQ1:PYP 2025Algebra>EasyAnswer optionseln(∣x∣)e^{ln(|x|)}eln(∣x∣)eln(x)e^{ln(x)}eln(x)ln(ex)ln(e^x)ln(ex)ln(e∣x∣)ln(e^{|x|})ln(e∣x∣)Correct AnswerOption 3Correct AnswerExplanation →
Q2:Sample PaperAlgebra > MediumQ2:Sample PaperAlgebra>MediumAnswer options{0,1}\{0, 1\}{0,1}{−1,0,1}\{-1, 0, 1\}{−1,0,1}{0}\{0\}{0}{1}\{1\}{1}Correct AnswerOption 1Correct AnswerExplanation →