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Q1:

2025: 3 June Shift 2

3D Geometry

Medium

Core

The angle at which the line, x−10=2−y−1=2z−3−2\frac{x-1}{0} = \frac{2-y}{-1} = \frac{2z-3}{-2} is inclined with the positive direction of z-axis is

Answer options
Option 1,4
Correct Answer
Explanation for 2025: 3 June Shift 2 MAT question 1

Q2:

2025: 3 June Shift 1

3D Geometry

Medium

Core

The shortest distance between the lines r⃗=i^+j^+λ(2i^−j^+k^)\vec{r} = \hat{i} + \hat{j} + \lambda(2\hat{i} - \hat{j} + \hat{k}) and r⃗=2i^+j^−k^+μ(4i^−2j^+2k^)\vec{r} = 2\hat{i} + \hat{j} - \hat{k} + \mu(4\hat{i} - 2\hat{j} + 2\hat{k}) is

Answer options
Option 1
Correct Answer
Explanation for 2025: 3 June Shift 1 MAT question 2

Q3:

2025: 3 June Shift 1

3D Geometry

Medium

Core

The Cartesian equation of the line passing through the point (1, 2, -1) and parallel to the line 5x−25=14−7y=35z5x - 25 = 14 - 7y = 35z is

Answer options
Option 2
Correct Answer
Explanation for 2025: 3 June Shift 1 MAT question 3

Q4:

2025: 3 June Shift 1

3D Geometry

Medium

Core

If the lines x−55λ+2=2−y5=1−z−1\frac{x - 5}{5\lambda + 2} = \frac{2 - y}{5} = \frac{1 - z}{-1} and x=y+1/22λ=z−13x = \frac{y + 1/2}{2\lambda} = \frac{z - 1}{3} are perpendicular, then the value of λ\lambda is equal to

Answer options
Option 2
Correct Answer
Explanation for 2025: 3 June Shift 1 MAT question 4

Q5:

2025: 2 June Shift 1

3D Geometry

Hard

Core

The value of λ\lambda so that the lines 1−x3=7y−142λ=z−32\frac{1-x}{3} = \frac{7y-14}{2\lambda} = \frac{z-3}{2} and 7−7x3λ=y−51=6−z5\frac{7-7x}{3\lambda} = \frac{y-5}{1} = \frac{6-z}{5} are at right angle, is:

Answer options
Option 1
Correct Answer
Explanation for 2025: 2 June Shift 1 MAT question 5

Q6:

2025: 2 June Shift 1

3D Geometry

Medium

Core

The foot of the perpendicular drawn from the point (1,6,3)(1,6,3) to the line x1=y−12=z−23\frac{x}{1} = \frac{y-1}{2} = \frac{z-2}{3} is

Answer options
Option 3
Correct Answer
Explanation for 2025: 2 June Shift 1 MAT question 6

Q7:

2025: 2 June Shift 1

3D Geometry

Medium

Core

If the direction ratios of two lines are a,b,ca, b, c and (b−c),(c−a),(a−b)(b-c), (c-a), (a-b) respectively, then the angle between these lines is:

Answer options
Option 3
Correct Answer
Explanation for 2025: 2 June Shift 1 MAT question 7

Q8:

2025: 30 May Shift 2

3D Geometry

Medium

Core

If a line makes angles α,β,γ\alpha, \beta, \gamma with the positive directions of the coordinate axes, then the value of cos⁡2α+cos⁡2β+cos⁡2γ\cos 2\alpha + \cos 2\beta + \cos 2\gamma is

Answer options
Option 3
Correct Answer
Explanation for 2025: 30 May Shift 2 MAT question 8

Q9:

2025: 30 May Shift 2

3D Geometry

Medium

Core

If z-coordinate of a point P on the line joining the points A (2, 2, 1) and B (5, 1, -2) is -1, than x-coordinate of point P is

Answer options
Option 2
Correct Answer
Explanation for 2025: 30 May Shift 2 MAT question 9

Q10:

2025: 30 May Shift 2

3D Geometry

Hard

Core

The coordinates of the image of the point P (5, 4, 2) in the line r⃗=(−i^+3j^+k^)+μ(2i^+3j^−k^)\vec{r} = (-\hat{i} + 3\hat{j} + \hat{k}) + \mu(2\hat{i} + 3\hat{j} - \hat{k}), where λ\lambda is a parameter, is

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Q11:

2025: 30 May Shift 1

3D Geometry

Medium

Core

If a line makes angles α\alpha, β\beta and γ\gamma with the positive directions of x-axis, y-axis and z-axis respectively, then sin⁡2α+sin⁡2β+sin⁡2γ\sin^2\alpha + \sin^2\beta + \sin^2\gamma is equal to

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Q12:

2025: 30 May Shift 1

3D Geometry

Medium

Core

Consider the line r⃗=−2i^+3j^+k^+λ(5i^−3j^−k^)\vec{r} = -2\hat{i} + 3\hat{j} + \hat{k} + \lambda(5\hat{i} - 3\hat{j} - \hat{k}). Match List-I with List-II

List-IList-II
(A) A point on the given line(I) (535,−335,−135)\left(\frac{5}{\sqrt{35}}, \frac{-3}{\sqrt{35}}, \frac{-1}{\sqrt{35}}\right)
(B) Direction ratios of the given line(II) (2, 3, 1)
(C) Direction cosines of the given line(III) (5, -3, -1)
(D) Direction ratios of a line perpendicular to given line(IV) (-2, 3, 1)

Choose the correct answer from the options given below:

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Q13:

2025: 30 May Shift 1

3D Geometry

Medium

Core

The shortest distance between the lines r⃗=(i^+2j^+3k^)+λ(2i^+3j^+4k^)\vec{r} = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda(2\hat{i} + 3\hat{j} + 4\hat{k}) and r⃗=(2i^+4j^+5k^)+μ(4i^+6j^+8k^)\vec{r} = (2\hat{i} + 4\hat{j} + 5\hat{k}) + \mu(4\hat{i} + 6\hat{j} + 8\hat{k}) is equal to

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Q14:

2025: 29 May Shift 2

3D Geometry

Medium

Core

The direction cosines of a line which makes equal angles with co-ordinate axes are:

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Q15:

2025: 29 May Shift 2

3D Geometry

Medium

Core

Let the equation of lines be as L1:r1⃗=a1⃗+λb1⃗L_1: \vec{r_1} = \vec{a_1} + \lambda\vec{b_1} and L2:r2⃗=a2⃗+λb2⃗L_2: \vec{r_2} = \vec{a_2} + \lambda\vec{b_2} such that a1⃗−a2⃗=2i^+4j^+4k^\vec{a_1} - \vec{a_2} = 2\hat{i} + 4\hat{j} + 4\hat{k} and b1⃗×b2⃗=8i^−4k^\vec{b_1} \times \vec{b_2} = 8\hat{i} - 4\hat{k}. Then the shortest distance between L1L_1 and L2L_2 is

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Q16:

2025: 29 May Shift 2

3D Geometry

Medium

Core

The vector equation of line passing through (2, -1, 3) and perpendicular to the lines

x−23=y−11=z+22\frac{x-2}{3} = \frac{y-1}{1} = \frac{z+2}{2} and x+3−4=y−5−3=z+12\frac{x+3}{-4} = \frac{y-5}{-3} = \frac{z+1}{2} is

(Here λ\lambda is a parameter)

Answer options

Q17:

2025: 27 May Shift 1

3D Geometry

Medium

Core

Cosine of the acute angle between the lines x−32=y−21=z−52\frac{x-3}{2} = \frac{y-2}{1} = \frac{z-5}{2} and x−16=y−3−3=z+62\frac{x-1}{6} = \frac{y-3}{-3} = \frac{z+6}{2} is

Answer options

Q18:

2025: 27 May Shift 1

3D Geometry

Medium

Core

Let L1L_1 and L2L_2 be two lines, represented as,

L1:r⃗=i^+j^+λ(2i^−j^+k^)L_1: \vec{r} = \hat{i} + \hat{j} + \lambda(2\hat{i} - \hat{j} + \hat{k}) and L2:r⃗=2i^+j^−k^+μ(4i^−2j^+2k^)L_2: \vec{r} = 2\hat{i} + \hat{j} - \hat{k} + \mu(4\hat{i} - 2\hat{j} + 2\hat{k}), where λ\lambda and μ\mu are scalars. Then which of the following are true?

(A) L1L_1 is perpendicular to L2L_2.

(B) L1L_1 is parallel to L2L_2.

(C) L1L_1 passes through the point (1, 1, 0)

(D) L2L_2 passes through the point (2, 1, -1)

Choose the correct answer from the options given below:

Answer options

Q19:

2025: 27 May Shift 1

3D Geometry

Medium

Core

Match List-I with List-II

List-IList-II
(A) Line : x=2y+1=z−1x = 2y + 1 = z - 1(I) Crosses xzxz plane at (1, 0, 1)
(B) Line : x+1=2y+1=zx + 1 = 2y + 1 = z(II) Crosses xzxz plane at (0, 0, 1)
(C) Line : x−1=2y=z+1x - 1 = 2y = z + 1(III) Crosses xzxz plane at (1, 0, -1)
(D) Line : x−1=2y=z−1x - 1 = 2y = z - 1(IV) Crosses xzxz plane at (1, 0, 2)

Choose the correct answer from the options given below:

Answer options

Q21:

2025: 26 May Shift 2

3D Geometry

Medium

Core

Which of the following statements are true?

(A) The vector equation of the line through the point (5, 2, -4) and parallel to the vector 3i^+2j^−8k^3\hat{i} + 2\hat{j} - 8\hat{k} is r⃗=(5i^+2j^−4k^)+λ(3i^+2j^−8k^)\vec{r} = (5\hat{i} + 2\hat{j} - 4\hat{k}) + \lambda(3\hat{i} + 2\hat{j} - 8\hat{k})

(B) Vector form of the equation of line x−53=y+47=z−62\frac{x-5}{3} = \frac{y+4}{7} = \frac{z-6}{2} is r⃗=(5i^−4j^+6k^)+λ(3i^+7j^+2k^)\vec{r} = (5\hat{i} - 4\hat{j} + 6\hat{k}) + \lambda(3\hat{i} + 7\hat{j} + 2\hat{k})

(C) The direction cosines of z-axis are (1, 1,0).

(D) If a line has direction ratios 2, -1, -2, then its direction cosines are -2/3, -1/3, -2/3.

Choose the correct answer from the options given below:

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Q22:

2025: 26 May Shift 2

3D Geometry

Medium

Core

The value of p so that the lines x−1−3=2y−22p=z−32\frac{x-1}{-3} = \frac{2y-2}{2p} = \frac{z-3}{2} and x−1−3p=y−14=6−z5\frac{x-1}{-3p} = \frac{y-1}{4} = \frac{6-z}{5} are at right angles is

Answer options

Q23:

2025: 26 May Shift 2

3D Geometry

Medium

Core

A line passes through the point with position vector 2i^−j^+4k^2\hat{i} - \hat{j} + 4\hat{k} and is in the direction of the vector i^+j^−2k^\hat{i} + \hat{j} - 2\hat{k}. The equation of the line in Cartesian form is:

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Q24:

2025: 22 May Shift 2

3D Geometry

Medium

Core

Acute angle between the lines x3=y4=z5\frac{x}{3} = \frac{y}{4} = \frac{z}{5} and x−14=y+1−3=z+105\frac{x-1}{4} = \frac{y+1}{-3} = \frac{z+10}{5} is:

Answer options

Q25:

2025: 22 May Shift 2

3D Geometry

Medium

Core

The co-ordinates of the point where the line x+33=y−1−1=z−5−5\frac{x+3}{3} = \frac{y-1}{-1} = \frac{z-5}{-5} cuts yzyz-plane are:

Answer options

Q26:

2025: 22 May Shift 2

3D Geometry

Medium

Core

Match List-I with List-II

List-IList-II
Equation of lineInformation
(A) r⃗=(3i^−2j^+k^)+λ(j^−2k^)\vec{r} = (3\hat{i} - 2\hat{j} + \hat{k}) + \lambda(\hat{j} - 2\hat{k})(I) Direction ratios are 2, 4, -1
(B) 2−x1=2y+14\frac{2-x}{1} = \frac{2y+1}{4}, z=2z = 2(II) Perpendicular to 2i^−j^+k^2\hat{i} - \hat{j} + \hat{k}
(C) x1=y−32=3−4z2\frac{x}{1} = \frac{y-3}{2} = \frac{3-4z}{2}(III) Passing through the point (3,−2,1)(3, -2, 1)
(D) r⃗=(3i^+2j^+k^)+λ(2i^+j^−3k^)\vec{r} = (3\hat{i} + 2\hat{j} + \hat{k}) + \lambda(2\hat{i} + \hat{j} - 3\hat{k})(IV) Direction ratios are -1, 2, 0

Choose the correct answer from the options given below:

Answer options

Q27:

2025: 22 May Shift 1

3D Geometry

Medium

Core

If a line makes angle π/3\pi/3 and π/4\pi/4 with the positive directions of x-axis and y-axis respectively, then the acute angle made by the line with positive direction of z-axis is

Answer options

Q28:

2025: 22 May Shift 1

3D Geometry

Medium

Core

Match List-I with List-II

List-IList-II
(A) Equations of line through (5,−4,6)(5, -4, 6) with direction ratios 3,7,23, 7, 2(I) x+35=y+7−4=z+26\frac{x+3}{5} = \frac{y+7}{-4} = \frac{z+2}{6}
(B) Equations of line through (3,7,2)(3, 7, 2) with direction ratios 5,−4,65, -4, 6(II) x−35=y−7−4=z−26\frac{x-3}{5} = \frac{y-7}{-4} = \frac{z-2}{6}
(C) Equations of line through (−5,4,−6)(-5, 4, -6) with direction ratios 3,7,23, 7, 2(III) x−53=y+47=z−62\frac{x-5}{3} = \frac{y+4}{7} = \frac{z-6}{2}
(D) Equations of line through (−3,−7,−2)(-3, -7, -2) with direction ratios 5,−4,65, -4, 6(IV) x+53=y−47=z+62\frac{x+5}{3} = \frac{y-4}{7} = \frac{z+6}{2}

Choose the correct answer from the options given below:

Answer options

Q29:

2025: 22 May Shift 1

3D Geometry

Medium

Core

If the lines 1−x3=y−22λ=z−32\frac{1-x}{3} = \frac{y-2}{2\lambda} = \frac{z-3}{2} and x−13λ=y−11=6−z5\frac{x-1}{3\lambda} = \frac{y-1}{1} = \frac{6-z}{5} are perpendicular, then λ\lambda is equal to

Answer options

Q30:

2025: 21 May Shift 2

3D Geometry

Medium

Core

The shortest distance between the following lines:

r⃗=(i^+j^−k^)+s(2i^+j^+k^)\vec{r} = (\hat{i} + \hat{j} - \hat{k}) + s(2\hat{i} + \hat{j} + \hat{k})

r⃗=(i^+j^+2k^)+t(4i^+2j^+2k^)\vec{r} = (\hat{i} + \hat{j} + 2\hat{k}) + t(4\hat{i} + 2\hat{j} + 2\hat{k}), where s and t are scalars, is:

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