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If the points (2,−3)(2, -3), (λ,−1)(\lambda, -1) and (0,4)(0, 4) are collinear, then the value of λ\lambda is :

Solution

✅ Correct Option: 4

Three points are collinear iff ∣λ−110412−31∣=0\begin{vmatrix} \lambda & -1 & 1 \\ 0 & 4 & 1 \\ 2 & -3 & 1 \end{vmatrix} = 0.

Expanding: λ(4+3)−(−1)(0−2)+1(0−8)=7λ−2−8\lambda(4+3) -(-1)(0-2) + 1(0-8) = 7\lambda - 2 - 8.

Wait, recompute: λ(4−(−3))+1(0−2)+1(0−8)=7λ−10=0\lambda(4-(-3)) + 1(0-2) + 1(0-8) = 7\lambda - 10 = 0, giving λ=107\lambda = \frac{10}{7}.

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