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The smaller of the areas enclosed by the circle x2+y2=4x^2 + y^2 = 4 and the line x+y=2x + y = 2 is

Solution

✅ Correct Option: 2

Circle x2+y2=4x^2+y^2=4 has radius 2; the line x+y=2x+y=2 passes through (2,0)(2,0) and (0,2)(0,2).

The smaller area is the circular segment cut off by the chord. It equals (quarter-disc area) minus (triangle area):

14π(2)2−12(2)(2)=π−2\frac{1}{4}\pi(2)^2 - \frac{1}{2}(2)(2) = \pi - 2.

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