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Let y=msin⁡rx+ncos⁡rxy = m\sin rx + n\cos rx. What is the value of d2ydx2\frac{d^2y}{dx^2}?

Solution

✅ Correct Option: 4

y=msin⁡rx+ncos⁡rxy = m\sin rx + n\cos rx.

dydx=mrcos⁡rx−nrsin⁡rx\frac{dy}{dx} = mr\cos rx - nr\sin rx.

d2ydx2=−mr2sin⁡rx−nr2cos⁡rx=−r2(msin⁡rx+ncos⁡rx)=−r2y\frac{d^2y}{dx^2} = -mr^2\sin rx - nr^2\cos rx = -r^2(m\sin rx + n\cos rx) = -r^2 y.

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