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A line makes the angle θ\theta with each of the xx and zz axes. If the angle β\beta which it makes with yy-axis is such that sin⁡2β=3sin⁡2θ\sin^2\beta = 3\sin^2\theta, then the value of cos⁡2θ\cos^2\theta is

Solution

✅ Correct Option: 3

Direction-cosine identity: cos⁡2α+cos⁡2β+cos⁡2γ=1\cos^2\alpha + \cos^2\beta + \cos^2\gamma = 1 with α=γ=θ\alpha = \gamma = \theta.

So 2cos⁡2θ+cos⁡2β=12\cos^2\theta + \cos^2\beta = 1, i.e., sin⁡2β=2cos⁡2θ\sin^2\beta = 2\cos^2\theta.

Given sin⁡2β=3sin⁡2θ=3(1−cos⁡2θ)\sin^2\beta = 3\sin^2\theta = 3(1-\cos^2\theta).

Equate: 2cos⁡2θ=3−3cos⁡2θ2\cos^2\theta = 3 - 3\cos^2\theta, so cos⁡2θ=35\cos^2\theta = \frac{3}{5}.

Note: Options (1) and (4) appear identical in the paper; we have selected option (3) which matches the computed value.

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