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The 7th and 9th terms of an arithmetic progression are 10 and 11, respectively. Find the 15th term.

Solution

✅ Correct Option: 2

In an Arithmetic Progression (AP), each term increases or decreases by the same amount called the common difference dd.

The formula for any term is:

an=a+(n−1)da_n = a + (n - 1)d

where aa is the first term and dd is the common difference.


The 7th term is 10 and the 9th term is 11.

From the 7th term to the 9th term, there are 2 steps in the sequence.

Change in value =11−10=1= 11 - 10 = 1

Number of steps =9−7=2= 9 - 7 = 2

Common difference:

d=12d = \frac{1}{2}

d=0.5d = 0.5


Using the 7th term to find the first term:

a7=a+(7−1)da_7 = a + (7 - 1)d

10=a+6(0.5)10 = a + 6(0.5)

10=a+310 = a + 3

a=7a = 7


Finding the 15th term:

a15=a+(15−1)da_{15} = a + (15 - 1)d

a15=7+14(0.5)a_{15} = 7 + 14(0.5)

a15=7+7a_{15} = 7 + 7

a15=14a_{15} = 14

Therefore, the 15th term is 1414.

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