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Consider the 15th term of the following Arithmetic Progression (AP).

A. 2, 7, 12, ...

B. 10, 7, 4, ...

C. 3, 8, 13, ..., 253

D. 1, -1, -3, -5, ...

Arrange the 15th term of the above APs in ascending order.

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

Using a15=a+14da_{15} = a + 14d:

A: 2+14(5)=722 + 14(5) = 72.

B: 10+14(−3)=−3210 + 14(-3) = -32.

C: 3+14(5)=733 + 14(5) = 73.

D: 1+14(−2)=−271 + 14(-2) = -27.

Ascending: −32<−27<72<73-32 < -27 < 72 < 73, that is B, D, A, C.

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