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A is twice as good a worker as B, and together they finish a piece of work in 16 days. In how many days will A alone finish the work?

Solution

✅ Correct Option: 1

Let B's one-day work be xx, so A's is 2x2x. Together 3x=1/163x = 1/16, giving x=1/48x = 1/48. A's rate is 2/48=1/242/48 = 1/24, so A alone finishes in 24 days.

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