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In an open ground, Mahesh walks 20 m towards North, turns left and goes 40 m. He turns to his left again and walk 50 m. How far is he from the starting point?

Solution

✅ Correct Option: 2

North 20 m, then left is West 40 m, then left again is South 50 m. Net vertical displacement =50−20=30= 50 - 20 = 30 m south; net horizontal =40= 40 m west.

Distance =302+402=2500=50= \sqrt{30^2 + 40^2} = \sqrt{2500} = 50 m.

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