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Solution

✅ Correct Option: 3

A number divisible by 15 must be divisible by both 3 and 5. All four end in 5, so check digit sums: 2365→162365 \to 16, 1375→161375 \to 16, 4365→184365 \to 18, 2275→162275 \to 16. Only 18 is a multiple of 3, so 4365 is divisible by 15.

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