Geometry

Miscellaneous

Medium

Find the relation between x and y such that the point (x, y) is equidistant from the points (2, 5) and (6, 8).

$8x+6y-71=0$

$5x+9y-67=0$

$7x+5y+84=0$

$2x+5y-46=0$

✅ Correct Option: 1

Equate the squared distances:

$(x-2)^2+(y-5)^2=(x-6)^2+(y-8)^2$

$-4x-10y+29=-12x-16y+100$

$8x+6y-71=0$

This is the perpendicular bisector of the segment joining the two points.

2022: 24 Aug Shift 1

The perimeter of the following figure is :

2026: 20 May Shift 1

The values of y for which the distance between the points P(10, y) and Q(2, 2) is 10 unit.

2025: 20 May Shift 2

Point A (4, 2) divides segment BC in the ratio 2:5. Coordinates of B and C are (2,6), (9,y) respectively. Find the value of y.

2026: 21 May Shift 1

If A is area of regular hexagon of side 4 cm, then value of 4A (in cm $^2$ ) is:

2023: 5 June Shift 2

In the figure, ABCDE and AEPQ are a regular pentagon and a square respectively. What is the measure of angle AQB ?

2025: 2 June Shift 2

If the distance between the points (2, -2) and (5, k) is 5 units, then one of the possible values of k shall be which of the following?

Solution